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Physics 18 Online
OpenStudy (anonymous):

A 600 kg car traveling at 30 m/s is going around a curve having a radius of 120m that is banked at an angle of 25.0°. The coefficient of static friction between the car's tires and the road is .3. What is the magnitude of the force exerted by friction on the car? A) 1590 N B) 3430 N C) 7240 N D) 7820 N E) 795 Answer: A Yeah, I have a test tomorrow and out of the whole guide of the exam this is the only question I've been havig issues with. I mean I know I already have the answer but I don't know how to get that answer, I get different ones but it seems that they're incorrect. Help me

OpenStudy (ookawaiioo):

Let me think

OpenStudy (anonymous):

I really don't know if that answe is correct, that's what my professor gave me.

OpenStudy (ookawaiioo):

I got 1748 N

OpenStudy (ookawaiioo):

I did something wrong

OpenStudy (ookawaiioo):

I got it

OpenStudy (ookawaiioo):

Your professor used EXACT measurements

OpenStudy (ookawaiioo):

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OpenStudy (ookawaiioo):

us =0.3 Mass= 600 kg gravity = 9.8 cos(25) = 0.90

OpenStudy (anonymous):

But why are we using m*g instead of normal force to calculate friction?

OpenStudy (anonymous):

I don't know, I thought I needed to divide normal force in Nx and Ny, right?

OpenStudy (ookawaiioo):

Force of normal = mass*gravity Normal(N) = mg

OpenStudy (ookawaiioo):

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OpenStudy (anonymous):

Those equations apply eventhough the car is moving?

OpenStudy (ookawaiioo):

yeah

OpenStudy (ookawaiioo):

any more questions?

OpenStudy (anonymous):

That'd be all, thanks!!

OpenStudy (ookawaiioo):

Good luck on your test

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