A 600 kg car traveling at 30 m/s is going around a curve having a radius of 120m that is banked at an angle of 25.0°. The coefficient of static friction between the car's tires and the road is .3. What is the magnitude of the force exerted by friction on the car? A) 1590 N B) 3430 N C) 7240 N D) 7820 N E) 795 Answer: A Yeah, I have a test tomorrow and out of the whole guide of the exam this is the only question I've been havig issues with. I mean I know I already have the answer but I don't know how to get that answer, I get different ones but it seems that they're incorrect. Help me
Let me think
I really don't know if that answe is correct, that's what my professor gave me.
I got 1748 N
I did something wrong
I got it
Your professor used EXACT measurements
|dw:1426798477592:dw|
us =0.3 Mass= 600 kg gravity = 9.8 cos(25) = 0.90
But why are we using m*g instead of normal force to calculate friction?
I don't know, I thought I needed to divide normal force in Nx and Ny, right?
Force of normal = mass*gravity Normal(N) = mg
|dw:1426799009563:dw|
Those equations apply eventhough the car is moving?
yeah
any more questions?
That'd be all, thanks!!
Good luck on your test
Join our real-time social learning platform and learn together with your friends!