A 600 kg car traveling at 30 m/s is going around a curve having a radius of 120m that is banked at an angle of 25.0°. The coefficient of static friction between the car's tires and the road is .3. What is the magnitude of the force exerted by friction on the car?
A) 1590 N
B) 3430 N
C) 7240 N
D) 7820 N
E) 795
Answer: A
Yeah, I have a test tomorrow and out of the whole guide of the exam this is the only question I've been havig issues with. I mean I know I already have the answer but I don't know how to get that answer, I get different ones but it seems that they're incorrect.
Help me
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OpenStudy (ookawaiioo):
Let me think
OpenStudy (anonymous):
I really don't know if that answe is correct, that's what my professor gave me.
OpenStudy (ookawaiioo):
I got 1748 N
OpenStudy (ookawaiioo):
I did something wrong
OpenStudy (ookawaiioo):
I got it
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OpenStudy (ookawaiioo):
Your professor used EXACT measurements
OpenStudy (ookawaiioo):
|dw:1426798477592:dw|
OpenStudy (ookawaiioo):
us =0.3
Mass= 600 kg
gravity = 9.8
cos(25) = 0.90
OpenStudy (anonymous):
But why are we using m*g instead of normal force to calculate friction?
OpenStudy (anonymous):
I don't know, I thought I needed to divide normal force in Nx and Ny, right?
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OpenStudy (ookawaiioo):
Force of normal = mass*gravity
Normal(N) = mg
OpenStudy (ookawaiioo):
|dw:1426799009563:dw|
OpenStudy (anonymous):
Those equations apply eventhough the car is moving?
OpenStudy (ookawaiioo):
yeah
OpenStudy (ookawaiioo):
any more questions?
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