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Mathematics 18 Online
OpenStudy (anonymous):

The hypotenuse of a right angle is rational always, sometimes, or never?

OpenStudy (solomonzelman):

I will give you 2 examples

OpenStudy (anonymous):

okay

OpenStudy (solomonzelman):

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OpenStudy (solomonzelman):

note: Integers are included in "rational" numbers.

OpenStudy (anonymous):

How do I know if its always, sometimes, or never?

OpenStudy (anonymous):

I just need a simple answer

OpenStudy (solomonzelman):

The hypotenuse of a right angle is always rational. that would mean that it is never a square root (unless you can simplify the square root to get rid of the root), and nor can it ever be any other irrational number. The hypotenuse of a right angle is never rational. that would mean that hypotenuse of any triangle is always irrational.

OpenStudy (solomonzelman):

sometimes rational, would mean that it can be rational or irrational.

OpenStudy (anonymous):

okay what about the area of a circle id rational? would that be sometimes?

OpenStudy (solomonzelman):

the area of a circle is found by \(\large\color{black}{ \displaystyle A=\pi r^2 }\) are you familiar with this formula ?

OpenStudy (anonymous):

yes

OpenStudy (solomonzelman):

k, and note: \(\large\color{black}{ \displaystyle \pi }\) is an irrational number.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

I am still confused bro

OpenStudy (solomonzelman):

you have a radius, pick any number. (choose one, for me please)

OpenStudy (anonymous):

4

OpenStudy (solomonzelman):

So \(\large\color{black}{ \displaystyle A= \pi \times 4^2 = 16\pi }\)

OpenStudy (solomonzelman):

Is \(\large\color{black}{ \displaystyle 16\pi }\) rational number or not ?

OpenStudy (anonymous):

no because of pi?

OpenStudy (solomonzelman):

yes, it is irrational

OpenStudy (solomonzelman):

now, choose any square root for me please.

OpenStudy (anonymous):

\[\sqrt{5}\]

OpenStudy (solomonzelman):

\(\large\color{black}{ \displaystyle A= \pi \times \sqrt{5}^2 = 5\pi }\)

OpenStudy (solomonzelman):

is that rational ?

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