Question

Eliminate the parameter.

x = \(\sqrt t\), y = 4t + 1

y = 4\(\sqrt x\) + 1, x \(\ge\) 0
y = 4\(\sqrt x\) - 1, x \(\ge\) 0
y = 4x^2 - 1
y = 4x^2 + 1

Answer 1

@perl @phi

Answer 2

Any ideas?

Answer 3

I know I have to solve for t in one of the equations

Answer 4

hint: it is easy to deal with the second to solve for t

Answer 5

\(x^2 = t\)
\(y = 4x^2 +1\)

Answer 6

eh forgot it, didn't we are looking for y as function of x

Answer 7

Is that right?

Answer 8

yes but when you do that you need certain restrictions

Answer 9

How would I find that?

Answer 10

actually not hehe, I'm must be spinning lol
you are safe :)

Answer 11

oh haha :)

Answer 12

thanks :)

Answer 13

np:)

Answer 14

i saw t=root(x) my head is not working lol