Question

Figure ABCD has vertices A(−3, 2), B(2, 2), C(2, −4), and D(−3, −2). What is the area of Figure ABCD?

Answer 1

Help please!

Answer 2

ok i guess i can help

Answer 3

Thanks!

Answer 4

yw the answer is ABCD has vertices A(-1,0), B(3,3), C(6,-1), and D(2,-4)
Let's see 3 important properties of a Square:
1) All sides are EQUAL.
2) The Diagonals are equal.3
3) Each Angle is equal to 90 degress.
.
To Prove the properties, let's draw the Square first with given vertices:

Answer 5

shoot i cant take out the pic hold on right quick

Answer 6

You want to attach a file?

Answer 7

yes

Answer 8

Each Angle is equal to 90 DEGREES
In this property we use Equation for Right Traingles, the Pythagorean theorem.
Just where the formula we used above is derived from.
For Triangle

Answer 9

1 more question...how many square units??

Answer 10

ok let me see

Answer 11

ALL satisfies the Pythagorean theorem, therefore all angles are 90 degrees:
.
Conclusion: ABCD that has vertices A(-1,0), B(3,3), C(6,-1), and D(2,-4) is a SQUARE.
Thank you,
sally

Answer 12

does that answer your question?

Answer 13

Yah! Thanks!!!!

Answer 14

your welcome =)

Answer 15

plus heres the site http://www.algebra.com/algebra/homework/Parallelograms/Parallelograms.faq.question.174494.html

Answer 16

I would give you a medal but I am not sure how......hehe anyways thanks!!!!

Answer 17

press best

Answer 18

the little blue butten by my name to the right

Answer 19

well bye i gave you a fan and a medal