Solve for x: 3|2x - 2| + 6 = 18.

x = 3, x = -3
x = 3, x = -1
x = 1, x = -1
x = -3, x = 1

Question

Solve for x: 3|2x - 2| + 6 = 18.

 x = 3, x = -3
 x = 3, x = -1
 x = 1, x = -1
 x = -3, x = 1

elise_a18 · Answer

@Nnesha

fibonaccichick666 · Answer

what have you tried?

elise_a18 · Answer

I thought C but idk

fibonaccichick666 · Answer

how did you arrive at that conclusion?

fibonaccichick666 · Answer

can you explain what you did, then I can see where you are confused

elise_a18 · Answer

I turned these equations into slope intercept form

fibonaccichick666 · Answer

ohk, so let's start there then.  In order to solve this, we want to try and end up with only something in absolute vlues on the left

dtan5457 · Answer

When you get problems like this, ISOLATE the absolute value.

That means to subtract the 6 to the other side, and divide by 3.

$$\left| 2x-2 \right|=4$$
Since this is absolute value, you must solve for when 4 is positive, and when 4 is negative.
$$\left| 2x-2 \right|=-4$$

You should get two answers

fibonaccichick666 · Answer

so do you remember the order of operations?

elise_a18 · Answer

yep PEMDAS

fibonaccichick666 · Answer

ok so when we solve for a variable, we need to reverse the order of operations.  I like to say SAD Mep :(  with a frowny face to remember.  so we undo starting with S.  In this case the absolute value is the same as our P, parentheses.  So, what do you think we will "undo" first?