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Mathematics 17 Online
OpenStudy (anonymous):

Any one know Calculus?

OpenStudy (jordan123321):

alil

OpenStudy (shamim):

Question plz!!!!!!

OpenStudy (anonymous):

kind of, i can try to help

OpenStudy (anonymous):

Find the volume of \[(x ^{2}+y ^{2}+z ^{2})^{2}\] with the center at the origin

OpenStudy (anonymous):

Well what i know is that you can combine the paraboloid.

OpenStudy (anonymous):

Use spherical coordinates

OpenStudy (anonymous):

its also a tripple integral.. im thinking convert it to a spherical cordinate system with d(row) d(theta) d(Phi)

OpenStudy (anonymous):

you are right

OpenStudy (anonymous):

\[p^2 = x^2+y^2+z^2\] \[x = p \sin \phi \cos \theta\] \[y = p \sin \phi \sin \theta\] \[z = pcos \phi\] so that's all the info they gave you right?

OpenStudy (anonymous):

radius makes me think of pi

OpenStudy (anonymous):

using pi, you can plug in 5, and use the others to solve the problem

OpenStudy (anonymous):

Can you just put the full question

OpenStudy (anonymous):

@iambatman

OpenStudy (perl):

that doesn't really make sense, `find the volume of that equation`

OpenStudy (perl):

find the volume bounded by that curve and ...

OpenStudy (anonymous):

Yeah, can you just take a pic of your question?

OpenStudy (anonymous):

i am trying to solve it

OpenStudy (perl):

find the volume of the interior of that three dimensional surface?

OpenStudy (perl):

$$ \Large \iiint_V dx dy dz $$

OpenStudy (anonymous):

Oh well then your p is \[0 \le p \le 5~~~~0 \le \phi \le \pi~~~~ 0 \le \theta \le 2 \pi\] mhm yeah that looks good

OpenStudy (perl):

better to change to spherical coordinates , as batman is doing. its much harder with rectangular coordinates. im just trying to set up the problem so its clear

OpenStudy (anonymous):

Don't bother with rectangular

OpenStudy (anonymous):

Remember we are treating p here as the radius that's why it's 0 to 5, if that makes sense to you

OpenStudy (anonymous):

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