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Mathematics 14 Online
OpenStudy (anonymous):

Is there anyone knowledgeable about sine, cosine, and tangent (trigonometry) that might be able to help me? last question

OpenStudy (mattyboyy):

I can try

OpenStudy (mattyboyy):

It just depends on the depth of the question lol

OpenStudy (anonymous):

Okay let me draw it out. Give me one sec. Thanks @mattyboyy

OpenStudy (anonymous):

|dw:1426817001178:dw|

OpenStudy (anonymous):

I have to find the values of w and x.

OpenStudy (anonymous):

Also, the 45 and 35 numbers in the figure are degrees (45 degrees and 35 degrees).

OpenStudy (anonymous):

@mattyboyy ??

OpenStudy (anonymous):

@dan815 Can you please help me?

OpenStudy (mattyboyy):

What about w and x though? the sine of w and x? cosine?

OpenStudy (anonymous):

It doesn't say. The directions just say "find the values of w and then x. Round the lengths to the nearest tenth and angle measures to the nearest degree.

OpenStudy (mattyboyy):

Yeah you're gonna need help from someone who knows more lol @sleepyjess you think you can help him really quick??

OpenStudy (sleepyjess):

oohhh trig... fun

OpenStudy (sleepyjess):

For the triangle in black, we can use the 45 45 90 rule|dw:1426817659124:dw|

OpenStudy (anonymous):

I'm super confused and I'm having some family issues at the moment so if I don't respond right away that's why

OpenStudy (sleepyjess):

Okay, that's fine :)

OpenStudy (anonymous):

Okay so the 45-45-90 rule states what exactly?

OpenStudy (sleepyjess):

45 45 90 states that the legs are equivalent and the hypotenuse is leg*\(\sqrt 2\)

OpenStudy (anonymous):

Okay so to find the value of w, would I use sine, cosine, or tangent?

OpenStudy (anonymous):

Cosine, right?

OpenStudy (sleepyjess):

To find the value of w, just look at the length of the other leg :)

OpenStudy (anonymous):

Oh truueeee I didn't even realize that. Okay... Now to find the value of x, what would the procedure be?

OpenStudy (sleepyjess):

to find x... to find x...

OpenStudy (sleepyjess):

Give me just a minute to remember this again B)

OpenStudy (anonymous):

Okay not a problem. Thanks. :)

OpenStudy (sleepyjess):

I think the best way to go about this would be to find the length of the w and x together the subtract out w|dw:1426818155585:dw|

OpenStudy (sleepyjess):

We know opposite and we're looking for adjacent, so we would use \(tan(35) = \dfrac{5.5}{adjacent}\)

OpenStudy (sleepyjess):

Does that make sense so far?

OpenStudy (anonymous):

Yes I think so.

OpenStudy (sleepyjess):

Okay :)

OpenStudy (sleepyjess):

Now we just need to solve for adjacent

OpenStudy (anonymous):

So when I input tan(35) into my calculator, I get 0.473815. Did I do something wrong?

OpenStudy (sleepyjess):

That should be correct, I don't have a calculator on me right now, but if that's what yours gave you :) Now multiply each side by adjacent This would be a lot easier if you could use cot, csc, and sec >.<

OpenStudy (anonymous):

What are cot, csc, and sec?

OpenStudy (sleepyjess):

other trig functions

OpenStudy (sleepyjess):

With cot (cotangent, also known as arctan) we could just do cot(35) = adjacent/5.5 (opposite), 1.428 = adjacent/5.5, multiply by 5.5, 7.854 = adjacent, subtract 5.5 to get x... but sadly, they won't let you do it that easily

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