Question

I do not understand someone please explain!


Let n be the middle number of three consecutive even integers. Write an expression for the sum of these integers.

Answer 1

consecutive numbers are numbers that are all in a row;

if the first of four consecutive numbers is x
the numbers will be x, x+1, x+2, x+3

Answer 2

In your case, you only need three consecutive numbers, and the middle one is n

Answer 3

I think I get it now. Would it be sum=3n?

Answer 4

if the sum of these 3 consec. integers is equal to certain number C and you want to find the numbers, I would write
\(\large\color{black}{ \displaystyle (x-1)+(x)+(x+1) =C }\)

Answer 5

making x the middle nuber

Answer 6

yes!,
the numbers are
n-1, n, n+1

so their sum is

(n-1) + n + (n+1) = 3n

Answer 7

But it 3 consecutive EVEN integers so wouldn't 2 be added each time?

Answer 8

yes, the 1's cancel out

Answer 9

and so it would be with n
\(\large\color{black}{ \displaystyle (n-2)+(n)+(n+2) =3n }\)

Answer 10

still 3n

Answer 11

Thank you!

Answer 12

Dammit, i didn't read the question correctly,

consecutive even numbers are
x, x+2, x+4, ...

so

(n-2) + n + (n+2) = same result

Answer 13

I miss-read it at first too

Answer 14

but, for me it is typical

Answer 15

(me too)