A proton and an electron in a hydrogen atom are separated by a distance of 5.3 x 10^-11 m. The magnitude and direction of electric field set up by the proton at the position of the electron is:
5.1 x10^11 N/C away from the proton
5.1 x10^11 N/C toward the proton
5.1 x10^10 N/C toward the proton
5.1 x10^10 N/C away from the proton
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OpenStudy (shamim):
Do u know the direction of electric field for a positive charge is outward?
OpenStudy (shamim):
And tge direction of electric field for a negative charge is inward???!!
OpenStudy (anonymous):
I think I got it. I got 5.1 x10^10 N/C toward the proton.
OpenStudy (anonymous):
Is that right?
OpenStudy (shamim):
Required formula for electric field is
E=(1/4*pi*afcylon not)q/r^2
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OpenStudy (shamim):
Proton has positive charge. Right????
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
I think my answer is right though.
OpenStudy (shamim):
So its electric field will b outward
OpenStudy (shamim):
So toward the proton is wrong!!!!
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OpenStudy (anonymous):
Ah, okay. I see.
OpenStudy (anonymous):
So it's away from the proton.
OpenStudy (shamim):
First option is right!!!
OpenStudy (anonymous):
Thanks!
OpenStudy (shamim):
Welcome!!!!
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