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Physics 57 Online
OpenStudy (anonymous):

A proton and an electron in a hydrogen atom are separated by a distance of 5.3 x 10^-11 m. The magnitude and direction of electric field set up by the proton at the position of the electron is: 5.1 x10^11 N/C away from the proton 5.1 x10^11 N/C toward the proton 5.1 x10^10 N/C toward the proton 5.1 x10^10 N/C away from the proton

OpenStudy (shamim):

Do u know the direction of electric field for a positive charge is outward?

OpenStudy (shamim):

And tge direction of electric field for a negative charge is inward???!!

OpenStudy (anonymous):

I think I got it. I got 5.1 x10^10 N/C toward the proton.

OpenStudy (anonymous):

Is that right?

OpenStudy (shamim):

Required formula for electric field is E=(1/4*pi*afcylon not)q/r^2

OpenStudy (shamim):

Proton has positive charge. Right????

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

I think my answer is right though.

OpenStudy (shamim):

So its electric field will b outward

OpenStudy (shamim):

So toward the proton is wrong!!!!

OpenStudy (anonymous):

Ah, okay. I see.

OpenStudy (anonymous):

So it's away from the proton.

OpenStudy (shamim):

First option is right!!!

OpenStudy (anonymous):

Thanks!

OpenStudy (shamim):

Welcome!!!!

OpenStudy (shamim):

Glad to help u!!!!!

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