Question

What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?
A) (x + 2)^2 + (y +3)^2 = 9
B) (x - 2)^2 + (y - 3)^2 = 16
C) (x - 2)^2 + (y - 3)^2 = 4
D) (x + 2)^2 + (y + 3)^2 = 16
E) (x- 2)^2 + (y +3)^2 = 9

Answer 1

(x-a)^2+(y-b)^2=r^2

Answer 2

the centre (a,b)=(-2,-3)

Answer 3

(x-(-2))^2+(y-(-3))^2=r^2
(x+2)^2+(y+3)^2=r^2

Answer 4

r^2=(x-a)^2+(y-b)^2
=(-2-(-2))^2+(0-(-3))^2
=(0)^2+(3)^2=9
(x+2)^2+(y+3)^2=9

Answer 5

A is the answer