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How do I proceed to solve this equation? sin(x)-cos^2(x)=0
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hint: cos^2(x)=1-sin^2(x)
\[\sin(x)-(1-\sin^2(x))=0 \\ \sin^2(x)+\sin(x)-1=0\] you have a quadratic in terms of sin(x) to solve
Many thanks! This is one of the properties of cos^2 I was not aware of.
It is a Pythagorean identity. sin^2(x)+cos^2(x)=1
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