Please help me
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OpenStudy (elise_a18):
do you know how to put equations into slope intercept form?
OpenStudy (domebotnos):
sort of
OpenStudy (elise_a18):
okay well gimme a minute
OpenStudy (domebotnos):
thank you
OpenStudy (elise_a18):
This is graphing inequalities I suppose
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OpenStudy (domebotnos):
i think
OpenStudy (elise_a18):
Okay so the first is already in y- intercept form and that would look like this on a graph because the y-intercept is -2 and the slope is -2 over 1.(up 2 and over -1) since it is an greater than or equal to symbol it should be a solid line shading upwards
OpenStudy (elise_a18):
OpenStudy (elise_a18):
do you understand?
OpenStudy (domebotnos):
yes thank you :)
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OpenStudy (elise_a18):
On the second equation, we have to put it into slope-int form and that is y=mx+b. B is the y-intercept and m is the slope.
\[y+x \ge0\]
\[y+x-x \ge -x+0\]
This would leave y by itself equaling
\[y \ge -x+0\]
OpenStudy (elise_a18):
So tell me. what would the slope and the y- int be?
OpenStudy (domebotnos):
so the slope is -1 over 1 and the y intercept is b which is 0
OpenStudy (elise_a18):
Good! So would it be a solid or dotter line shading which way?
OpenStudy (elise_a18):
dotted*
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OpenStudy (domebotnos):
they would both be solid lines because they are both inequalities are greater than and equal to.
OpenStudy (elise_a18):
Good! So plotting both these on a graph would look like this and you can see the intersecting point is at (-2,2)