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do you know how to put equations into slope intercept form?
sort of
okay well gimme a minute
thank you
This is graphing inequalities I suppose
i think
Okay so the first is already in y- intercept form and that would look like this on a graph because the y-intercept is -2 and the slope is -2 over 1.(up 2 and over -1) since it is an greater than or equal to symbol it should be a solid line shading upwards
do you understand?
yes thank you :)
On the second equation, we have to put it into slope-int form and that is y=mx+b. B is the y-intercept and m is the slope. \[y+x \ge0\] \[y+x-x \ge -x+0\] This would leave y by itself equaling \[y \ge -x+0\]
So tell me. what would the slope and the y- int be?
so the slope is -1 over 1 and the y intercept is b which is 0
Good! So would it be a solid or dotter line shading which way?
dotted*
they would both be solid lines because they are both inequalities are greater than and equal to.
Good! So plotting both these on a graph would look like this and you can see the intersecting point is at (-2,2)
Great job @domebotnos :)
thank you, you too as well :D
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