Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (domebotnos):

Please help me Medal and fan :) http://prntscr.com/6izhly

OpenStudy (elise_a18):

do you know how to put equations into slope intercept form?

OpenStudy (domebotnos):

sort of

OpenStudy (elise_a18):

okay well gimme a minute

OpenStudy (domebotnos):

thank you

OpenStudy (elise_a18):

This is graphing inequalities I suppose

OpenStudy (domebotnos):

i think

OpenStudy (elise_a18):

Okay so the first is already in y- intercept form and that would look like this on a graph because the y-intercept is -2 and the slope is -2 over 1.(up 2 and over -1) since it is an greater than or equal to symbol it should be a solid line shading upwards

OpenStudy (elise_a18):

OpenStudy (elise_a18):

do you understand?

OpenStudy (domebotnos):

yes thank you :)

OpenStudy (elise_a18):

On the second equation, we have to put it into slope-int form and that is y=mx+b. B is the y-intercept and m is the slope. \[y+x \ge0\] \[y+x-x \ge -x+0\] This would leave y by itself equaling \[y \ge -x+0\]

OpenStudy (elise_a18):

So tell me. what would the slope and the y- int be?

OpenStudy (domebotnos):

so the slope is -1 over 1 and the y intercept is b which is 0

OpenStudy (elise_a18):

Good! So would it be a solid or dotter line shading which way?

OpenStudy (elise_a18):

dotted*

OpenStudy (domebotnos):

they would both be solid lines because they are both inequalities are greater than and equal to.

OpenStudy (elise_a18):

Good! So plotting both these on a graph would look like this and you can see the intersecting point is at (-2,2)

OpenStudy (elise_a18):

OpenStudy (elise_a18):

Great job @domebotnos :)

OpenStudy (domebotnos):

thank you, you too as well :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!