Find the area of the trapezoid. Leave your answer in simplest radical form. https://lh5.ggpht.com/TYBnTWyQ_w3tbzi3AuSpGJnx4I0wtYpOapBmfZ-l7IlvYg-S2n2fRV6aKlLnyG7ZX6eF4Xg=s89 a. 40√3 b. 16√3 c. 24√3 d. 32√3
yeah i'll see if this gets answered over night.. maybe if i put a girl as my picture i'll get more answers, huh? ^^
is this ur picture
you just help girls?
everyone
this isn't me, i just need help.
if i could umderstand this i would help out....but i am only in 7th grade sooooo idk
a tip for you, just right click any hot girls pictures you may think are fishy.. and click search google. you'll find how popular they are and they're most likely fake.
eeewww okay i didnt click on this fur ur nasty porno gurl piic
well as soon as i put it on i had 12 ppl max viewing this. coincidence?
umm...maybe cause some men want some buuuut im not a man...im just here to help :/
r u a boy or girl
dude
me or flight? if ur speaking to flight then he is a boy...i know it
right
yeah but @flight98 if i could help i would...but umm im confused on this myself...lol well umm best wishes and u seriously need to change that pic...its nasty porno pic...sooo Cya!
Ok. BACK ON TOPIC
Heres is the drawing:|dw:1426839959651:dw|
is that ur pic @flight98
yeah
Lets find the side which attaches the triangle and the rectangle. We know that the hypotnuse is 8, angle is 60. We can find the side using SIN \[\sin\theta=\frac{O}{H}\]\[\sin(60)=\frac{O}{8}\]\[O=8\times \sin(60)\]\[O=6.93ft\]
ok..
ur just a kid
@flight98, thank you for changing your picture
of course
16 tho
Now, lets find the side below the triangle. We can use the pythagorous theorum for this: \[c^2=a^2+b^2\]\[8^2=6.93^2+b^2\]\[b^2=8^2-6.93^2\]\[b=\sqrt{8^2-6.93^2}\]\[b=3.99ft\]
Now, lets look at the picture now|dw:1426840407303:dw|
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