Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

can someone help me please :)

OpenStudy (anonymous):

OpenStudy (anonymous):

@iGreen

OpenStudy (ahsome):

Ok. If we say that equation A is parallel to equation B, what do they both have that is similar?

OpenStudy (anonymous):

i don't think so ?.

OpenStudy (igreen):

Okay, what's the slope of y = 1/5x - 10?

OpenStudy (anonymous):

I'm really not sure , can you help

OpenStudy (anonymous):

@iGreen

OpenStudy (igreen):

Okay, it's in the form of y = mx + b, where 'm' is the slope..so what's the slope?

OpenStudy (anonymous):

b over m + y over m

OpenStudy (anonymous):

@iGreen

OpenStudy (igreen):

y = 1/5x - 10 Slope is the number right before 'x', and what's that?

OpenStudy (anonymous):

1/5x

OpenStudy (igreen):

Yes, but we don't include 'x'..the slope is 1/5.

OpenStudy (igreen):

Parallel lines have the SAME slope, so the slope of our new line must also be 1/5.

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

so does that mean A AND D are out ?

OpenStudy (igreen):

Yep, you got it.

OpenStudy (anonymous):

okay . :) I'm thinking its C.

OpenStudy (igreen):

Now we can plug the slope and the point into point-slope form and simplify. \(y - y_1 = m(x - x_1)\) Where \(y_1\) is the y-value of the point, \(x_1\) is the x-value of the point, and \(m\) is the slope. So we have: \(y + 16 = \dfrac{1}{5}(x - 15)\) Distribute 1/5 into the parenthesis: \(y + 16 = \dfrac{1}{5}x - 3\) Subtract 16 to both sides, what's -3 - 16?

OpenStudy (igreen):

Yep, it will

OpenStudy (anonymous):

yay its C

OpenStudy (anonymous):

thank you sir :)

OpenStudy (igreen):

-3 - 16 = -19 \(y = \dfrac{1}{5}x - 19\)

OpenStudy (igreen):

No problem \(\Huge\ddot\smile\) \(\bbox [10pt, lime, border:5pt solid black]{\huge\cal\color{red}\succ\color{blue}{Welcome\ to\ \color{#00A1FF}{Open}\color{#329932}{Study!\color{red}\prec}}}\) You can give medals by clicking 'Best Response'.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!