Mathematics
11 Online
OpenStudy (melissa_something):
Complete the square and write equation in standard form and give center and radius. -___- PLEASE HELP
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OpenStudy (melissa_something):
x^2+y^2+2x+8y+17=19 Please show steps :'(
OpenStudy (anonymous):
y do u have a sad face at the end of the ques
OpenStudy (melissa_something):
This is sooo difficult @The.Great.Don
OpenStudy (melissa_something):
What equation is this?
OpenStudy (rock_mit182):
you're setting up oranges with oranges and apples with apples
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OpenStudy (rock_mit182):
[(x^2 + 2x + c^2) + (y^2 + 8y + d^2) \]
OpenStudy (rock_mit182):
c^2 = 1 and d^2 = (4)^2
OpenStudy (rock_mit182):
(x^2 + 2x +(1)^2) + (y^2 + 8y + (4)^2)= 19
OpenStudy (rock_mit182):
\[(x^2+ 2x +1) + (y^2 + 8y + 16)=19 \]
OpenStudy (melissa_something):
Yes combining like terms!!
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OpenStudy (rock_mit182):
Are you awere of : c^2 + d^2 =17
or (1)^2 + (4)^2 = 17
OpenStudy (rock_mit182):
so we do not need 17 anymore cause we already have it in the equatiaon as the sum of c^2 +d ^2
OpenStudy (rock_mit182):
yeah right
OpenStudy (rock_mit182):
exactly is the clue combining then find the c^2 and b^2 and after that you're almost done
OpenStudy (rock_mit182):
\[(x^2+ 2x + 1^2) \] can be written as: \[(x+1)^2 \]
and \[y^2+8y+(4)^2\] can be witten as:
\[(y+4)^2 \]
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OpenStudy (rock_mit182):
therefore :
\[(x+1)^2 + (y+4)^2 = 19 \]
OpenStudy (rock_mit182):
and that's all
OpenStudy (melissa_something):
Wow thank you..
OpenStudy (rock_mit182):
now could you find the center and radius: r ^2 = 19 --> r =sqroot (19)
OpenStudy (rock_mit182):
and the center is way easy..
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OpenStudy (melissa_something):
Oh gosh @rock_mit182 im still blurry how you got the 1..& OMG! My bad 19 was supposed to be 9!
OpenStudy (rock_mit182):
did you find the center ?
OpenStudy (rock_mit182):
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