A stone is dropped into some water and a ripple circle of radius r is formed and slowly expands. At the moment the radius is exactly 2m, what rate is the radius of the circle increasing?
The perimeter increases at 3m/s, sorry
what you think
A stone is dropped into some water and a ripple circle of radius r is formed and slowly expands. At the moment the radius is exactly 2m, what rate is the radius of the circle increasing? ` The perimeter increases at 3m/s` <--- is this correct?
A' = 2pi r
"The perimeter increases at 3m/s" why not use the circumference formula C = 2*pi*r instead of the area formula
yes that would be easier
$$ \Large {C =2\pi r \\ \frac{dC}{dt} = 2\pi \cdot \frac{dr}{dt} \\ \therefore \\ 3 = 2\pi \cdot \frac{dr}{dt} \\ \frac{dr}{dt}= \frac{3}{2\pi} } $$ it turns out that it does not matter what is the actual radius
sorry internet crashed
still need help
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