@Nnesha @satellite73
Isn't it 180 degrees + 41 degrees?
Sure, @Here_to_Help15 :D
Ask as a new question, please
@Data_LG2 can you help ?
|dw:1426901322368:dw| Find theta or the angle of direction usin trig tan ratio \(\sf \large tan\ \theta = \frac{opposite}{adjacent}\\ \theta=tan^{-1}(\frac{opposite}{adjacent})\) your opposite is 4 ft and your adjacent is 6ft plug them in the formula i gave above
I get what you mean just that "tan" always throws me off
its*
okay don't worry :D so the diagram is clear? all those opposite and adjacent stuff?
Diagram is superb its just the solving it.
@Data_LG2 ?
oh okay great then so do you know the trig ratio SOH CAH TOA? sin 0 = opposite/hypotenuse cos 0 = adjacent/hypotenuse tan 0 = opposite/adjacent i just make 0 as theta for now
Sin cos and tan i dont know why i never get those. I see them and i get stuck, being homeschooled sucks :/
Ok look can you explain how you get opposite hypotenuse adjacent
don't worry i had the same problem before :) what you do, so that you won't get confuse, just focus on the position of the angle or the theta. The opposite of the angle will always be the opposite side and the opposite of the 90 degree angle will be the hypotenuse. Then the remaining side will be the adjacent side . Now, depending on the given values and the position of the angle, you'll determine whether to use sin, cos or tan
For example your problem: |dw:1426902090445:dw|
|dw:1426902180125:dw|
Join our real-time social learning platform and learn together with your friends!