http://www.studentbounty.com/pastpapers/Cambridge%20International%20Examinations%20%28CIE%29/International%20AS%20and%20A%20Level/Mathematics%20%289709%29/2014%20Jun/9709_s14_qp_31.pdf Q10
part ii)
so how can i help you? you need help with these questions?
what grade mathematics are you takeing in your coureses
AHEM , how can i help?? you need help wwith your quiz?
y=(10e^-1/2x)*sin4x use product rule to find the derivative. y'=10e^-1/2x*d/dx(-1/2x)*sin4x+10e^-1/2x*4cos4x=-5e^-1/2xsin4x+40e^-1/2xcos4x at stationary point dy/dx=0
so 5e^-1/2xsin4x=40e^-1/2xcos4x tan4x=8 sovle for x.
@Abmon98 get ready your gonna need a calculator do you have one?
so 5e^-1/2xsin4x=40e^-1/2xcos4x tan4x=8 sovle for x. so if you solve for x.. what do you get?
yes, tan^-1(8)=4x tan(180+x)=tan(x) so 4x=82.87,180+82.87 x=20.71,65.71
for part ii) is it going to be some sort of an arithmetic sequence.
ok..so is that your answer? did you get it? make sure the equation is right!
yes, my answers for x are correct.
-APPLAUDE- okay there you have it!!
a=20.719 d=65.719-20.719=45 so the general equation for the arithmetic sequence is 20.719+(n-1)45>25
GOOD LUCK ON YOUR QUIZ!! TTYL
thanks :) @prettyprincess1 but should we convert our answer into radians.
u might!! any way your welcome!! if u like pls give me a medal!! i didmy best!! @Abmon98
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