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Find the rectangular coordinates of the point with the polar coordinates (\(\sf 3, \dfrac 32 \pi)\)
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@phi
do you recall the conversion formulas?
I know that rectangular form is < a, b >
thats right, and polar is (r,t) or radius and angle
|dw:1426950675944:dw|
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I would need to use x = r cos \(\theta\) and y = r sin \(\theta\) right?
correct
x = 3 cos(3pi/2) y = 3 sin(3pi/2) should do it then
Okay, would that be it?
that would be it yes.
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Thanks :)
3pi/2 is what, 270 degrees? so the cos parts are 0 and the sin is -1 if memory serves
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