Question

If one side of a square is x-2, what is the value of x if the perimeter is 6x+7? Help

Answer 1

Here you are given a two equations with which you can create a system to solve.
You only need to translate the second one.
How can you write an equations which connects the perimeter with one of the sides of the square ?

Answer 2

4 times the x-2?

Answer 3

4(x-2)=6x+7?

Answer 4

I think im wrong

Answer 5

Yes, thats it !

Answer 6

Really?

Answer 7

Yes, now you have to solve the system.

Answer 8

X=-15/2?

Answer 9

Can you show the full way of going there ?

Answer 10

Is it wrong?

Answer 11

Yes. The answer can't be a negative number because if x is negative, then x-2 will also be negative and therefore the side of the square will be negative which can't actually happen

Answer 12

Can you help me find the answer? I don't get this :(

Answer 13

You need to solve 4( x-2 ) = 6x + 7 right ?

Answer 14

Yes

Answer 15

Lets see..

Answer 16

4( x-2 ) = 6x + 7 <=> 4x - 8 = 6x + 7 <=> 2x = - 15 <=> x = - 15 / 2

Answer 17

So, there is something wrong about the problem :)

Answer 18

It's on the radical review, I think it has something to do with radicals

Answer 19

Dude, if the one side of the square is negative then there is no square.
You can see yourself that if we assume that our square can have a side of - 15 / 2 - 2 = - 19 / 2 then its perimeter is 4 * ( - 19 / 2 ) = - 19 * 2 = - 38
But - 38 can't be the value of a perimeter although - 38 = 6 * ( - 15 / 2 ) + 7