Let \(f_1, f_2,f_3\) be continuously differentiable functions from \(\mathbb R^4\) to \(\mathbb R\). Give suffice conditions so that the equations \(f_1(x,y,z, t)=0\\f_2(x,y,z,t)=0\\f_3(x,y,z,t)=0\) can be solved for x,y,z in term of t. Please, help
@SithsAndGiggles @amistre64 @phi @perl
i wouldnt even know where to start with this at the moment. srry
It's Ok. Thanks anyway. :)
@nincompoop Thanks but it is not the same as my problem. :)
My attempt: Let \(f_1,f_2,f_3:\mathbb R^4 \rightarrow \mathbb R\) . Let \(f:\mathbb R^4\rightarrow \mathbb R^3\), \(f=(f_1,f_2,f_3)\) . Hence f is smooth function
The derivative matrix of f is \[D(f)=\left[\begin{matrix}\dfrac{\partial f_1}{\partial x}&\dfrac{\partial f_1}{\partial y}&\dfrac{\partial f_1}{\partial z}\\\dfrac{\partial f_2}{\partial x}&\dfrac{\partial f_2}{\partial y}&\dfrac{\partial f_2}{\partial z}\\\dfrac{\partial f_3}{\partial x}&\dfrac{\partial f_3}{\partial y}&\dfrac{\partial f_3}{\partial z}\end{matrix}\right]\]
But I don't know where to go from this. :(
How about this @rational @zzr0ck3r
I have no idea either. I really hate analysis and much prefer topology.
I will take topology next semester, is it hard?? @zzr0ck3r
I don't think so. It is much more general.
I find it makes analysis easier, but we are not this far yet.
any recommendation for preparing for the course?
Munkres Topology
it's a staple
are they books? any site?
yeah it's a book. I don't really watch videos of lectures, I learn much more from the books.
You can readily find it if you google
for free even! The book is super old.
I will, thanks for the tips. :)
If you have any questions next term, tag me:) I love that stuff
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