A square loop, 9.6 m on a side, is made of
copper wire, 0.7 mm in radius.
A 2.4 T magnetic field, perpendicular to
the loop is increasing at the rate of 0.3 T/s.
The resistivity of copper is 1.7 × 10−8 Ω m .
Find the induced current.
Answer in units of A.

Question

A square loop, 9.6 m on a side, is made of
copper wire, 0.7 mm in radius.
A 2.4 T magnetic field, perpendicular to
the loop is increasing at the rate of 0.3 T/s.
The resistivity of copper is 1.7 × 10−8 Ω m .
Find the induced current.
Answer in units of A.

anonymous · Answer

You need to know induced voltage on the loop, which is related with magnetic flux change on the loop
$$V=-\frac{d\Phi}{dt}$$
here $$\Phi$$ is magnetic flux, $$B*A$$, here area is constant and only magnetic field is changing, thus
$$V=-A\frac{dB}{dt}$$
here A - area of square loop. Ohms rule
$$I=V/R$$
and 
$$R=\rho\frac{L}{S}$$
here L-lengthn of wires, S-cross section area of the wire. just put things together.