Question

Please help! Medal will be given.

Picture will be attached in another post.

Answer 1

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Answer 2

@chris992 - I can't see what you posted.

Answer 3

OH

Answer 4

The graph doesn't have much info to find the equation of. The only point i know is the y-intercept (0,4).

Answer 5

If i can point out the vertex, i can autmatically find the equation of a parabola.
What i prefer to do:
Start by writing down the vertex equation of a parabola
\(y=(x-h)^2+k\)
Where h and k are the vertex. Since the graph is already given, pin point the vertex of the parabola.

Answer 6

@Zale101 - Is the vertex (3, -5)?

Answer 7

From what i'm observing, i thinks so..

Answer 8

\(y=(x-3)^2-5\)
Foil \((x-3)^2\) and subtract 5 to get the parabola equation in a standard form.

Answer 9

@Zale101 - That would be \[y = x ^{2} - 6x + 4\]

Answer 10

Correct :)

Answer 11

What is the y-intercept of y=x^2-6x+4 ?

Answer 12

Hint: Set x=0

Answer 13

@Zale101 - It is (0, 4) according to my graphing calculator.

Answer 14

\(y=x^2-6x+4 \)
\(y=0^2=6(0)+4\)
\(y=4\)
Y-intercept is (0,4) which it's shown on your graph. SO the standard for of your equation is y=x^2-6x+4

Answer 15

standard form*

Answer 16

@Zale101 - Thank you so much!

Answer 17

No problem. Next time i would like to see you type and show your work here when i asked you to foil and subtract.

Answer 18

@Zale101 - I apologize.

Here's my work:
\[y = (x-3)^{2} - 5\]
y = (x-3)(x-3) - 5
y = (x)(x) + (x)(-3) + (-3) (x) + (-3)(-3)
\[y = (x ^{2} - 3x - 3x + 9) - 5\]
\[y = x ^{2} - 6x + 4\]

Thanks again!