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Mathematics 8 Online
OpenStudy (anonymous):

here is a question

OpenStudy (anonymous):

@Loser66

OpenStudy (loser66):

Why do you repost it?

OpenStudy (anonymous):

because i need help. cant really work on it. i always get confuse

OpenStudy (loser66):

ok, tell me the definition of a ring?

OpenStudy (loser66):

Since you post this problem twice, I know you do want to know what is going on. However, you need go step by step by YOURSELVES. I will guide you the process and explain carefully. But you must work out on it. The very first step is definition of a ring, type it out, PLEASE

OpenStudy (anonymous):

a ring is an algebraic structure consisting of two operations .+ and *

OpenStudy (anonymous):

@Loser66

OpenStudy (loser66):

ok, next: properties of a ring?

OpenStudy (anonymous):

associativity, closure identity inverse commutativity

OpenStudy (loser66):

ok, now, check one -by -one closure: what does closure mean?

OpenStudy (anonymous):

it means that if you + are * if result is \[\in q\] then it is closed

OpenStudy (loser66):

it means if a, b in the set, then (a+b) in the set also.

OpenStudy (anonymous):

yes

OpenStudy (loser66):

Now, your problem Let (a,b,c,d) and (e,f,g,h) are 2 elements in the set . That is a, b,c,d,e,f,g,h all are rational numbers, ok?

OpenStudy (loser66):

By define, if you add them together, you have a new one , it is (a+e, b+f, c+g, d+h) ok?

OpenStudy (loser66):

Now tell me, a is a fraction, e is a fraction also, hence if a +e, do you have a fraction?

OpenStudy (anonymous):

yes.

OpenStudy (loser66):

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