calc help!!
@ybarrap help please!
Since the difference between each x datapoint is not uniform, we'll need to use this formula: $$ \int_{a}^{b} f(x)\, dx \approx \frac{1}{2} \sum_{k=1}^{N} \left( x_{k+1} - x_{k} \right) \left( f(x_{k+1}) + f(x_{k}) \right) $$ Fill in the following to apply this formulat: $$ \begin{matrix} x&f(x)&x_{k+1}-x_{k}&f(x_{k+1}+f_{k})&x_{k+1}-x_{k}\times f(x_{k+1}+f_{k})\\ 1&4& & & \\ 3&8&?&?&?\\ 4&6&?&?&?\\ 6&10&?&?&?\\ 7&10&?&?&?\\ 9&12&?&?&?\\ 10&16&?&?&?\\ \end{matrix} $$ Fill in all the \(?'s\) then sum that last column and divide by two to get your answer. see - http://en.wikipedia.org/wiki/Trapezoidal_rule#Non-uniform_grid
wow im a little confused hahaha
Do you understand the formula?
i dont get what k would be
Oh Ok, so k is just the \(k^{th}\) \(x\) or \(f(x)\) value. For example, for \(k=1,k=2\), \(x_1=1,x_2=3\) and also \(f(x_1)=4,f(x_2)=8 \) and so on. Does that make sense?
can we do the first upper left box? so i know what im doing? pleasee
Here is a corrected table (a few problems with indices and parenthesis): $$ \begin{matrix} x&f(x)&x_{k+1}-x_{k}&f(x_{k+1})+f(x_{k})&(x_{k+1}-x_{k})\times f(x_{k+1})+f(x_{k})\\ 1&4& & & \\ 3&8&?&?&?\\ 4&6&?&?&?\\ 6&10&?&?&?\\ 7&10&?&?&?\\ 9&12&?&?&?\\ 10&16&?&?&?\\ \end{matrix} $$
yes, go ahead and start
|dw:1426983886475:dw|
Join our real-time social learning platform and learn together with your friends!