Question

Convert the following complex number into its polar representation: 2+2i

Answer 1

Complex number to polar form:
a + bi --> \(r[\cos\theta+i\sin\theta]\)

Answer 2

\(r=\sqrt{a^2+b^2}\)

Answer 3

Wouldn't square root 2^2+2^2 = 2 square root 2

Answer 4

\(\theta=Arctan(\large\frac{b}{a})\) if a>0
\(\theta=Arctan(\large\frac{b}{a})+\pi\) if a<0

Answer 5

Yes, it would.

Answer 6

which is what option a. has

Answer 7

Yep.

Answer 8

oh ok i guess that would make the answer a. then but how do you figure out the stuff in the parenthesis?