Question

log9(9)+log9(1/9)

Answer 1

are those 9s exponents or bases?

Answer 2

bases...sorry didn't know how to type it

Answer 3

\[\huge\rm log_9 (9) + \log_9 \frac{ 1 }{ 9 }\]
first you can change addition to multiplication

Answer 4

ok, got it. Remember your log laws here, \[\log_{9}9=1 \]

Answer 5

And \[\log_{9}{\frac{1}{9}}=-1\]

Answer 6

and -1 +1 =0

Answer 7

product property \[\huge\rm log_b x + \log_b y = \log_b (x \times y)\]
\[\huge\rm log_b x - \log_b y=\log_b \frac{ x }{ y }\]
and if there is negative sign you can change that to division

Answer 8

Okay. Daughter figured the answer was 0. Couldn't figure out how log9 1/9 became -1

Answer 9

heres how: \[\frac{1}{9} = 9^{-1}, so \log_{9}9^{-1}=-1\]

Answer 10

you guys rock! She gets it. Thanks. (mom clueless)

Answer 11

thanks! medal please!