Question

The Derivative of y=x^sinx...

Answer 1

did you try logarithmic differentiation

Answer 2

When you do this:\[
x^{\sin x} = (e^{\ln x})^{\sin x} = e^{\ln x \sin x}
\]It becomes a bit easier.

Answer 3

is the derivative cosx/x

Answer 4

Not quite

Answer 5

is this correct (sinx)x^(sinx - 1)(cosx)

Answer 6

stow your working
ill check

Answer 7

show*

Answer 8

yes

Answer 9

\[logy=\log(x)^{sinx} \rightarrow logy=sinxlogx\]

Answer 10

diff.w.r.t.x

Answer 11

yep now @denizen continue

Answer 12

hmm

Answer 13

(sin x )(cos x)(x^(sin x -1))=1/2 sin (2x) x^(sinx -1)

Answer 14

\[i/y dy/dx=sinx/x+xcosx\]

Answer 15

log y=log(x^sin x)
log y=sin x .log x
diff. with respect to x
(1/y)(dy/dx)=cos x.log x + sin x /x)
dy/dx=(x^sin x) (cos x .log x + sin x/x)
it's the answers of prob.