Ask your own question, for FREE!
Chemistry 9 Online
OpenStudy (ahsome):

Find substance given mass percentage

OpenStudy (ahsome):

We are told that substance A is comprised of Oxygen, sulfur and Nickel 40% is Oxygen, 21% is Sulfur, and 38% is Nickel. Find the chemical formula of the substance.

OpenStudy (ahsome):

@dtan5457?

OpenStudy (ahsome):

@korosh23

OpenStudy (somy):

take percentages as masses and use mole formula mole =mass / molecular mass

OpenStudy (somy):

find mole of all the three given atoms

OpenStudy (somy):

make sure all moles that u got are full numbers or at least close to full if mole = 1.1 you can round it to 1 if its equal to = 1.9 you can round it to 2 but if its anything in between, you have to multiply all moles to a number that can change decimal in one (or two or three if all have decimals that need to be changed) of your moles to a full number

OpenStudy (somy):

but not to confuse you do the first step find the mole & show it to us what u got then we'll what we gotta do afterwards

OpenStudy (ahsome):

@Somy, i'm really confused. Can you please explain?

OpenStudy (somy):

Your compound has O, S, Ni 40% is Oxygen 21% is Sulfur 38% is Nickel now take these percentages as masses use the formula mole = mass / molecular mass I'll do one of the for you and you gotta do the rest so mole= 40 / 16 mole = 2.5 This is for Oxygen now do same thing with S and Ni

OpenStudy (ahsome):

@Somy, i'm really confused. Can you please explain?

OpenStudy (somy):

i did explain... now you gotta do the working

OpenStudy (ahsome):

@Somy, I don't understand what you mean by this: "take percentages as masses and use mole formula mole =mass / molecular mass find mole of all the three given atoms" I understand what you are trying to say. I just don't know how that solve this equations

OpenStudy (ahsome):

So, do I turn 40% to 40g?

OpenStudy (somy):

i showed you in working of Oxygen The percentage given - you consider it as mass of the atom yes

OpenStudy (ahsome):

so, 40/16 = 2.5 21/32 = 0.66 38/59=0.64 Now what?

OpenStudy (somy):

good now as you need there are no full numbers multiply all the answers by 2 & show me what you got

OpenStudy (ahsome):

@Somy, 5, 1.32, 1.28

OpenStudy (somy):

no good because we cant round off to full number in this case now multiply them all by 3 this time

OpenStudy (ahsome):

I multiplied them by six. That works fine \[2.5\times 6=15\]\[0.66\times 6=3.96\]\[0.64\times 6=3.85\]

OpenStudy (ahsome):

@Somy

OpenStudy (ahsome):

@hartnn @shamim @Somy?

OpenStudy (somy):

oh very good :) so u can round off 3.96 and 3.85 to 4

OpenStudy (ahsome):

Now what. Please help @Somy, @shamim

OpenStudy (ahsome):

@Somy?

OpenStudy (ahsome):

@Somy, PLEASE, IM begging :(

OpenStudy (ahsome):

@Somy ?

OpenStudy (ahsome):

;(

OpenStudy (somy):

im here :D well now you know that O -15, S- 4 and Ni -4 thus your formula will be so your compound will have 15 O atoms, 4 S atoms and 4 Ni atoms

OpenStudy (ahsome):

And we can simplify that? Cause the answer is NiSO4

OpenStudy (ahsome):

@Somy?

OpenStudy (somy):

hmm wait i'll calculate myself coz there is some error

OpenStudy (ahsome):

Ok. THANK YOU

OpenStudy (ahsome):

What did you get @Somy

OpenStudy (somy):

this is weird i mean there is no way i can get 4 O atoms

OpenStudy (dan815):

I am here you have nothing to worry about it anymore

OpenStudy (jhannybean):

*crickets*

OpenStudy (dan815):

We are told that substance A is comprised of Oxygen, sulfur and Nickel 40% is Oxygen, 21% is Sulfur, and 38% is Nickel. Find the chemical formula of the substance. where is the other 1%

OpenStudy (ahsome):

@dan815, not sure. Let me check again...

OpenStudy (ahsome):

40.3, 21.7, 38

OpenStudy (ahsome):

That should help, @Somy

OpenStudy (ahsome):

@Somy?

OpenStudy (ahsome):

@Somy?

OpenStudy (somy):

im still getting same ratio

OpenStudy (ahsome):

Then I am not sure. It definately says thats it

OpenStudy (somy):

i guess so then

OpenStudy (ahsome):

How would we do the same thing with 10.1% Carbon, 40.4% Oxygen and 49.5% Nickel?

OpenStudy (ahsome):

Assume we have 10.1g of carbon, divide by 12?

OpenStudy (somy):

yeah same way

OpenStudy (ahsome):

So, wait \[10.1/12=0.84\]\[40.4/16=2.525\]\[49.5/58.7=0.84\]Now what?

OpenStudy (ahsome):

@Somy

OpenStudy (somy):

multiply by a number that will change them all to a whole number

OpenStudy (ahsome):

0.84 * 5 = 4.2 0.84 * 5 = 4.2 2.5 * 5 = 10

OpenStudy (somy):

seems good enough

OpenStudy (ahsome):

Then, we divide everything by 2?

OpenStudy (somy):

what is the answer that you have for it?

OpenStudy (ahsome):

NiCO3

OpenStudy (jfraser):

once you have found the moles of each (0.84, 0.84, and 2.5) \(instead\) of multiplying by a random number and hoping to get whole numbers when you're done, \(divide\) each one of those by the smallest of the set to maintain the molar ratio. Take 0.84 moles C, 0.84 moles Ni, and 2.5 moles O, and divide them all by 0.84

OpenStudy (jfraser):

That way you get a molar ratio of Ni:C:O as 1:1:3.005, which easily rounds to 1:1:3

OpenStudy (ahsome):

That makes WAY more sense. THANK YOU @JFraser :D

OpenStudy (somy):

oh goooooooooood i totally forgot this part! @JFraser thanks a loooot @Ahsome and im soooo sorry

OpenStudy (jfraser):

YW

OpenStudy (ahsome):

Its fine @Somy, you helped a bunch too! Is it bad to assume 100g tho?

OpenStudy (jfraser):

that's exactly what you should do

OpenStudy (jfraser):

you could assume any starting mass, but we use "100g" as the starting amount because it's easy to find 10.1% of 100g

OpenStudy (ahsome):

Ahh, K. I would just state that as an assumption?

OpenStudy (jfraser):

if you have to explain the process, yes

OpenStudy (ahsome):

Ahh, K :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!