Question

Sketch a triangle with lengths of sides 4, 5, and 6 units. Is the triangle acute, right, or obtuse? How do you know?

Answer 1

did you sketch it?

Answer 2

xD good idea

Answer 3

:)

Answer 4

but how can i use the pythagorean theorem?

Answer 5

\(\Large{4^2 + 5^2 = 6^2}\)
try it

Answer 6

\(\Large{4^2?}\)

Answer 7

ok so 16 and 25

Answer 8

add them

Answer 9

but what do you do with 41?

Answer 10

u find the square root right?

Answer 11

ok first tell me what is \(\Large{6^2}\)

Answer 12

36

Answer 13

so is \(\Large{41 = 36 ?}\)

Answer 14

No

Answer 15

so not a right triangle

Answer 16

ok i knew that but how do i find out if it is an obtuse or acute

Answer 17

if its bigger or smaller than C^2?

Answer 18

sketch it first

Answer 19

ok

Answer 20

very well

Answer 21

just wondering if there is an easier way mathematically

Answer 22

than to have to sketch and change the sketch so all sides are appropriately drawn

Answer 23

so its obtuse?

Answer 24

I found this:
Compare the hypotenuse to the longest side given in the problem. If the longest given side is shorter than the hypotenuse, the given triangle is acute. If it is longer than the hypotenuse, the given triangle is obtuse.

Answer 25

ah ok

Answer 26

thx

Answer 27

the hypotenuse is 6?

Answer 28

\(\Large{5^2 < 6^2~right?}\)

Answer 29

yes true

Answer 30

therefore, it is obtuse

Answer 31

the given sides are 4 and 5
the longest is 5
since it is less than the hypotenuse, it is an acute triangle

Answer 32

4,5, and 6 right?

Answer 33

the sides are 4 and 5
the hypotenuse is 6
5<6 so acute

Answer 34

how did you find the hypotenuse?

Answer 35

sorry

Answer 36

\(\Large{4^2 + 5^2 = 6^2}\)

Answer 37

but \[4^2+5^2\neq6^2\]

Answer 38

\(\Large{5^2 = 25}\)
\(\Large{6^2 = 36}\)
\(\Large{25<36}\)

Answer 39

ok

Answer 40

thx

Answer 41

since the longest given side is < the hypotenuse, it is an acute triangle

Answer 42

ok

Answer 43

i gtg hope i helped

Answer 44

yep it did