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graph the hyperbola with equation ((x+2)^2/49)-((y+3)^2/4=1 PLEASE HELP WILL GIVE MEDALS
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\[((x+2)^2/49)-((y+3)^2/4)=1\]
we have to perform this traslation first: \[\left\{ \begin{gathered} X = x + 2 \hfill \\ Y = y + 3 \hfill \\ \end{gathered} \right.\]
where X, Y are the new coordinates
using those new coordinates, we can write your hyperbola as follows: \[\frac{{{X^2}}}{{{7^2}}} - \frac{{{Y^2}}}{{{2^2}}} = 1\]
how do I graph it? I have a TI-84 and I cant figure it out
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here is the graph of both coordinate systems: |dw:1427057006792:dw|
wont they be parabolas?
in the XOY system the graph of your hyperbola is:|dw:1427057203128:dw|
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