graph the hyperbola with equation ((x+2)^2/49)-((y+3)^2/4=1 PLEASE HELP WILL GIVE MEDALS

Question

anonymous · Answer

$$((x+2)^2/49)-((y+3)^2/4)=1$$

michele_laino · Answer

we have to perform this traslation first:
$$\left\{ \begin{gathered}
  X = x + 2 \hfill \
  Y = y + 3 \hfill \ 
\end{gathered}  \right.$$

michele_laino · Answer

where X, Y are the new coordinates

michele_laino · Answer

using those new coordinates, we can write your hyperbola as follows:
$$\frac{{{X^2}}}{{{7^2}}} - \frac{{{Y^2}}}{{{2^2}}} = 1$$

anonymous · Answer

how do I graph it? I have a TI-84 and I cant figure it out

michele_laino · Answer

here is the graph of both coordinate systems:
|dw:1427057006792:dw|

anonymous · Answer

wont they be parabolas?

michele_laino · Answer

in the XOY system the graph of your hyperbola is:|dw:1427057203128:dw|