The drama club sold bags of candy and cookies to raise money for the spring show. Bags of candy cost $8.00, and bags of cookies cost $3.50, and sales equaled $45.00 in total. There were 33 more bags of cookies than candy sold.
Find the number of bags of candy and cookies sold by the drama club.
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OpenStudy (anonymous):
is this problem written correctly?
OpenStudy (anonymous):
no its 3 bags more
OpenStudy (anonymous):
lol ok makes sense now
OpenStudy (anonymous):
yah
OpenStudy (anonymous):
So to do this problem just set up i simple algebraic equation
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OpenStudy (anonymous):
\[8x+3.5(x+3)=45\]
OpenStudy (anonymous):
Where x is the number of bags bought
OpenStudy (anonymous):
so 8x+3.5x+10.5=45
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
now can you solve for x?
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OpenStudy (anonymous):
x=3
OpenStudy (anonymous):
but there are 2 answews @TheDream
OpenStudy (anonymous):
Look at the equation and think about the problem. You see that x is the number of candy bags. And you know the number of cookies bought is x+3 so the second answer is?
OpenStudy (anonymous):
can you help me with another question
OpenStudy (anonymous):
@TheDream
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OpenStudy (anonymous):
Sure what is it
OpenStudy (anonymous):
A group of adults and kids went to see a movie. Tickets cost $6.50 each for adults and $2.00 each for kids, and the group paid $27.00 in total. There were 5 fewer adults than kids in the group.
Find the number of adults and kids in the group.
OpenStudy (anonymous):
@TheDream
OpenStudy (anonymous):
Same concept as before
OpenStudy (anonymous):
number of adults = x, number of kids = x+5
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