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Algebra 19 Online
OpenStudy (anonymous):

Give the Laplace transform of -4x-3 0≤x and x<2 2 2≤x

OpenStudy (anonymous):

Do you know about laplace tables ?

OpenStudy (anonymous):

i do. but what about the boundaries?

OpenStudy (anonymous):

i have a table with me right now, but I don't know how to do it with the boundaries.

OpenStudy (anonymous):

our teacher assigned this to us without even teaching us how to do it, and its due tomorrow....

OpenStudy (anonymous):

...to my knowledge, there shouldn't be a way different approach when it has boundaries. Outside the "when x is between this, L(f(t) = this". Let me look up some of my courses really quick but I seriously doubt there's anything special to it.

OpenStudy (anonymous):

ok.

OpenStudy (anonymous):

Nothing in my book about it. Well, they're not really that hard. All you need to do is bring the equation into a form that can be easily converted using the table. For the first one the transform is -4/p^2 -3/p in that interval. For the second it is 2/s.

OpenStudy (anonymous):

so all you do is combine the first and second term and that's it?

OpenStudy (anonymous):

Just say that the L( f(t) ) = -4/p^2 -3/p for x between 0 and 2 and it equals 2/p when x is less than 2.

OpenStudy (anonymous):

That's what I'd say. I'm not 100% sure but that's my 2 cents.

OpenStudy (anonymous):

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