Question

Check my trig question

Answer 1

FInd all other 5 trig signs if sec=-9/4, in the interval pi/2<theta<pi

cos=-4/9
sin=sqrt65/9
csc=9(sqrt65)/65
tan=-sqrt65/4
cot=-4(sqrt65)/65

Answer 2

@jim_thompson5910 @jdoe0001

Answer 3

hmmm

Answer 4

that interval is pretty much the 1st Quadrant

the secant can't be negative, since all sides are positive on the 1st Quadrant though

Answer 5

hmmm ohjhh shoot.. I read 0 dohhh
is \(\pi\) so is the 2nd quadrant

Answer 6

Yeah, is the rest right?

Answer 7

sec

Answer 8

all of them are correct, just that the tangent needs to be positive
because \(\bf sec(\theta)=\cfrac{hypotenuse}{adjacent}\to -\cfrac{9}{4}\to \cfrac{9}{-4}\to \cfrac{9=c}{-4=a}
\\ \quad \\
c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\impliedby \textit{2nd quadrant, "b" is positive}
\\ \quad \\
+\sqrt{9^2-(-4)^2}=b\implies \sqrt{65}=b\)

Answer 9

hmmm actually wait a sec... I see the -4 dohh
tangent is correct as well =)

Answer 10

lol, thanks again ;p

Answer 11

yw