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Mathematics 9 Online
OpenStudy (kj4uts):

Find the product of the complex numbers. Express your answer in trigonometric form. z1=5(cos(pi/2)+i sin(pi/2)) z2=2(cos(5pi/6)+i sin(5pi/6))

OpenStudy (kj4uts):

OpenStudy (tkhunny):

What's the theorem?

OpenStudy (anonymous):

to find the product of that in trigonometric (polar) form, you would have to multiply the r values together in z1 and z1 and then add the angle

OpenStudy (anonymous):

z1 and z2, sry typo

OpenStudy (anonymous):

no, 5*2 = 10

OpenStudy (anonymous):

and that is the r value for the product

OpenStudy (kj4uts):

oh sorry typo

OpenStudy (anonymous):

now, to find the new angle, just add pi/2 and 5pi/6

OpenStudy (kj4uts):

4pi/3

OpenStudy (anonymous):

If you are going to find quotient later for another question, do the exact opposite, divide the r values and subtract angles

OpenStudy (anonymous):

and yes that is correct

OpenStudy (kj4uts):

that looks like choice c. then.

OpenStudy (anonymous):

yeah

OpenStudy (kj4uts):

so the angles are the numbers in front of the parenthesis and the r values are those in the parenthesis?

OpenStudy (anonymous):

no, the r value is the number outside of parenthesis (length of vector; in your question, that is 5 and 2), and the angle is in the parentheses.

OpenStudy (anonymous):

this should help

OpenStudy (kj4uts):

ok thank you :)

OpenStudy (anonymous):

You're welcome :)

OpenStudy (kj4uts):

can I ask you one more question... I can open another question up if you want.

OpenStudy (anonymous):

sure go ahead

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