Question

f(x)=e^x+e^-x...

Why is the critical value of this function 0?

Answer 1

Deriv = e^x*e^-x+e^x*-e^-x

or e^x*e^-x-e^x*e^-x

Answer 2

A way of thinking of it is that f(x) is an even function because we can clearly see that f(x)=f(-x). We already know that e^x is one to one, so it can only have a critical value at x=0 if it has any at all.

Answer 3

Tj, what's up with your derivative? :o
It looks a little crazy

Answer 4

Whoops thought it was * I did mult rule hahah

Answer 5

Ignore that madness

Answer 6

Oh lol :)

Answer 7

Okay thanks for that, that makes sense!