Question

Find this integral

Answer 1

\[\int\limits_{1}^{e^2} lnp/ 5p\]

Answer 2

Substitute \(u = \ln(p)\).

Answer 3

Yeah I tried that!

Answer 4

It should definitely work.

Answer 5

I keep getting (e^4 - 1)/10 but apparently it is incorrect

Answer 6

First, let's just find the antiderivative.\[\frac{1}{5}\int \frac{\ln(p)}{p}dp\]\[u:=\ln(p), du = \frac{1}{p}dp\]\[\equiv \frac{1}{5}\int u ~du\]\[= \frac{1}{5}\frac{u^2}{2} = \frac{u^2}{10} \Longleftrightarrow \frac{\ln^2(p)}{10}\]

Answer 7

Ooohohhh

Answer 8

It should be 2/5 then