Question

Simple Vector Problem

Answer 1

Diagram + Question. Helo, @amistre64

Answer 2

am = mb and nc = bn by midpoint property

Answer 3

Yup

Answer 4

therefore by vector addition .... mb + bn = mn

Answer 5

not to sure about b tho :)

Answer 6

Yup

Answer 7

Me neither

Answer 8

MQ is the segment formed by joining two mid points. I guess, we need to relate any theorem based on this..? :/

Answer 9

Me neither

Answer 10

I think i got it.

Answer 11

Maybe
\(AD+DQ=AM+MQ\)
\(BC +CQ=MB+MQ\)

Answer 12

that might only be applicable in a parallelagram

Answer 13

\(AD+DQ+BC=CQ=AM+MQ+MB+MQ\)
Does that work?

Answer 14

Whoops, last one should be BM

Answer 15

\[AD+DQ+BC+CQ=AM+MQ+BM+MQ\]

Answer 16

im not sure, just tired and not that bright these days :)

Answer 17

Take like terms?
\[AD+DQ+BC+CQ=AM+BM+2MQ\]

Answer 18

\[AD+DQ+BC-QC=AM-MB+2MQ\]\[AD-DC+BC=-AB+2MQ\]

Answer 19

Not sure about the last part, @amistre64. @Kainui?

Answer 20

MQ = MB + BC + CQ
MQ = MA + AD + DQ

2 MQ = MB + BC + CQ + MA + AD + DQ

MB = - MA
CQ = - DQ

2 MQ = BC + AD

Answer 21

@IrishBoy123, if MB = -MA, should MB-Ma = 2MB?

Answer 22

of course it should.

the minus sign in case it is not clear is because of the direction. MB goes in the opposite direction to MA so adding them yields zero.

Answer 23

Ahh, I see. So since you add them together, it uends up being 0, @IrishBoy123?

Answer 24

indeed