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Does the series converge or diverge. Use ratio test or root test.
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\[a_{1}=1, a_{n+1}=\frac{ 1+\ln(n) }{ n}a _{n}\]
whats stopping you from using ratio test ?
I dont know what to do with the an in an+1
take the ratio and it goes away
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What would an be then?
doesn't matter \[\large \lim\limits_{n\to \infty }\left|\dfrac{a_{n+1}}{a_n}\right| =\lim\limits_{n\to \infty }\left|\dfrac{\frac{1+\ln n}{n}a_n}{a_n}\right| = \lim\limits_{n\to \infty }\left|\dfrac{1+\ln n}{n}\right| \]
wouldn't it just be infinity over infinity then?
yes you may use L'hopital rule
Okay, so it would be 1/n, which be equal 0, so the series is convergent?
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Yep!
THANKS SO MUCH! :D
yw
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