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Algebra 19 Online
OpenStudy (anonymous):

Use the Law of Sines to solve for a to the nearest tenth.

OpenStudy (anonymous):

myininaya (myininaya):

Well first you can find angle A right? You know the sum of the angles of a triangle is 180 deg.

myininaya (myininaya):

Then you can use either: \[\frac{\sin(A)}{a}=\frac{\sin(B)}{b} \text{ or } \frac{\sin(A)}{a}=\frac{\sin(C)}{c} \] to find a

OpenStudy (anonymous):

okay well i know A is 47, but how do i do the Sin(A)/a stuff?

myininaya (myininaya):

use either of the equations i mentioned and isolate first the a

myininaya (myininaya):

for example remember how to solve for x here: \[\frac{5}{x}=\frac{4}{3} \] you can multiply both sides by x and 3 \[5(3)=4(x) \\ 3(5)=4x\] then divide both sides by 4 \[\frac{3(5)}{4}=x\]

myininaya (myininaya):

do the same thing here pretend you take the first equation I mentioned you can multiply both sides by b and a then afterwards like I did here divide both sides by sin(B)

OpenStudy (anonymous):

k

myininaya (myininaya):

You can show me what you get as the final answer and I will check it

myininaya (myininaya):

or show me any of your work leading to that answer.

myininaya (myininaya):

\[\frac{\sin(A)}{a}=\frac{\sin(B)}{b} \\ b \sin(A)=a \sin(B) \\ \frac{b \sin(A)}{\sin(B)}=a\] the solving part is over you just have to round that evaluation with a calculator

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