I am hopelessly confused. Can someone please help me with Trig? What's the value of n?
use a trigonometric relationship
for example sin=opposite/hypotenuse
I tried that, and if I did it even remotely correct it didn't match any of the answers.
show me what you set up and put into your claculator
For sin I didn't know if I should have put 90 or not but I did...sin(90) After that though nothing matched and I just don't understand it at all. For opposite and hypotenuse I do know would be 5 and 10 correct?
we're trying to find the value of angle n
I know, but how would I want to set that up then? I watched videos my teacher had on her message board but it was entirely different.
what would sin(angle n) be?
keep in mind the sin of any angle is the side opposite over the hypotenuse
Would I set it up sin(5/10) then? I got .48
you're supposed to be using arcsin
or inverse sin
\(\sin(n)=\dfrac{5\sqrt3}{10}\\arcsin(sin(n))=arcsin(\dfrac{5\sqrt3}{10})\\n=arcsin(\dfrac{5\sqrt3}{10})\)
If I calculate that I get like 1/10 but my options are 1/2 squareroot 3/3 square root 3/2 and square root 3
can you post the full question? does it ask for n or N?
cause I'm getting <N=pi/3
or 60 degrees
It is asking in the questions, what is the value of Sin N?
oh, it's just \(\dfrac{5\sqrt3}{10}\) can you simplify that fraction?
I got .069
don't just enter it into your calculator there's a basic reduction that can be done we want to keep it in terms of the radical 3
I guess it'd be easier to see if I rewrite it. \(\dfrac{5\sqrt3}{10}=\dfrac{5}{10}*\sqrt3\)
radical 3/2?
aye aye
Thanks! In one question though it gave me the lengths of the sides but is asking me to find the degree of an angle. It is a right angle was there any special way to go about that at all or just go by what you showed me how to do?
you can either use inverse trig functions or side ratios for example, if it's a 45-45-90 triangle and you have 1 side, you can figure out the others' same if it's a 30-60-90
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