Please Help!! No Idea how to work this out!! :( medal and fan if possible!!
If an object is dropped from a height of 195 feet, the function h(t) =−16t^2+195 gives the height of the object after t seconds. When will the object hit the ground? a. 3.49 s c. 13.96 s b. 1.75 s d. 6.98 s
h(t)= 16t^2 + 195
when it hits the ground its height is 0
0=16t^2+195
solve for time
I am not sure how :/
do i have to divide or something?
@dan815 please? I literally have no idea how to solve for the time
yeah we want to isolate for t
both sides of the equations are equal we can the same thing to both sides and it will still be equal
we can do*
0-195=-16t^2+195 -195 -195=-16t^2 -195/-16 = -16/-16 * t^2 (-195/-16)=t^2 t=sqrt(195/16)
ok, I did that the only part i didnt make it to was t=sqrt(195/16) 3.49?
here is a good place to check your answers http://www.wolframalpha.com/input/?i=0%3D-16t^2%2B195
3.49 is right
thank you, i have one more, but using what you just taught me, i already solved it. would you mind checking it just realy quick?
nevermind, i just used the wolfram alpha xP
good :)
Join our real-time social learning platform and learn together with your friends!