How many triangles can be formed knowing that A=40 degrees C=75 degrees c=20
I'm getting two triangles..am I right?
@dan815 @jdoe0001 @jim_thompson5910
@Jhannybean
Just curious how you would even approach this?
You would use the laws of sin, and then there are a bunch of rules you follow that are suppose to determine this. I want to check my answer, through.
Oh wait I didn't see C and c I was thinking that was an angle of 20 and it didn't equal 180 hahaha. Ignore me :-)
@StudyGurl14
Haha np.
@butterflydreamer
hold on a sec. I'm not excellent at this, but I'll check your answer.
Using the laws of sin, I got a=13.3, b=18.76, h=12.05
H<a<b, two triangles..?
Online answer key is actually saying one triangle, but I don't know why.
you got a right. still checking other stuff
h should equal a
I think...I think you should take a look at these websites. They'll probably help you more than I can. I really hate the ambiguous case with law of sines. http://regentsprep.org/Regents/math/algtrig/ATT12/lawofsinesAmbiguous.htm http://homepages.ius.edu/MEHRINGE/M126/Notes%20Fall%202012/Section%207.2%20The%20Ambiguous%20Case%20of%20the%20Law%20of%20Sines.htm
h=bsinA right?
Because my h is a whole 1 off from a
I don't know...i'll check my pre-calc book. i don't think we had an h value when i did it a few months ago
my a and b values are correct though right?
yeah, your a and b are correct
But h, i got 12.05, did you really get h=a?
hold on a sec. my camera is taking forever to transfer...
take a look at this
bsinA = 12.06 that's what i got
yah but a=13.3 lol
hmmm...now i'm confused...
I don't get it...the answer should b two solution
I'd ask your teacher.
Yeah, I'm getting two solutions as well. I'm gonna stick with it.
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