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what is the problem if you can use a calculator ?
lol
you don't need the absolute value in this case.
\(\large\color{blue}{\displaystyle \int_{1}^{2}{ \rm Ln}(x^2+1)~dx}\)
to do this one, use integration by parts as your first step. (if you want to do by hand)
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you know there is a site wolframalpha.com (?) :) go for it.... if you want to do it by hand and need help doing it by hand you can always ask... :D
http://www.wolframalpha.com/input/?i=evaluate+integral+1+to+2++Ln+%28x%5E2%2B1%29+dx
i got the question wrong last time
well, I don't think wolfram can be wrong. I haven't seen such a thing before.
and "log" is assumed a natural log, ... so you are good.
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thank you(:
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