write the polar equation in rectangular form r=-12 cos theta
hint multiply r on both sides
so -12 times r?
\[r^2=-12 r \cos(\theta)\]
I bet you know what rcos(theta) equals and r^2 equals in terms of x and y.
im lost sorry
\[x^2+y^2=r^2 \\ rcos(\theta)=x \\ rsin(\theta)=y\]
\[\tan(\theta)=\frac{y}{x}\]
you only need two of the equations I listed
for this particular equation
so this is the answer?
what is?
tan(0)=x/y
how did you get
\[r^2=-12 r \cos(\theta)\] do you see the r^2 and the rcos(theta)?
tan(theta)
I gave you two equations above that told you what those were in terms of x and y
do you want to try again to apply those equations I gave to your equation
\[r=-12 \cos(\theta) \\ r \cdot r =r \cdot (-12 \cos(\theta)) \\ r^2=-12 r \cos(\theta) \\ \text{ replace } r^2 \text{ with } x^2+y^2 \\ \text{ replace } r \cos(\theta) \text{ with } x \\ \text{ this is \because } r^2=x^2+y^2 \text{ and } r \cos(\theta)=x \]
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