Landon is standing in a hole that is 6.5 m deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y =–0.05x² + 4.5x – 6.5, where x is the horizontal distance of the rock, in meters, from Landon and y is the height, in meters, of the rock above the ground. How far horizontally from Landon will the rock land? Round your answer to the nearest hundredth of a meter.
A. 82.03 m
B. 6.50 m
C. 90.00 m
D. 88.53

Question

Landon is standing in a hole that is 6.5 m deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y =–0.05x² + 4.5x – 6.5, where x is the horizontal distance of the rock, in meters, from Landon and y is the height, in meters, of the rock above the ground. How far horizontally from Landon will the rock land? Round your answer to the nearest hundredth of a meter. 
A. 82.03 m
B. 6.50 m
C. 90.00 m
D. 88.53

amistre64 · Answer

how far above the ground is the rock when it lands?

anonymous · Answer

Its at 45 so I was thinking that it might be around 82.03 but I'm not completely sure.

amistre64 · Answer

when the rock lands on the ground, the height above the ground that the rock is is 0.  therefore y=0 giving us:

0 = -0.05x^2 + 4.5x - 6.5

which is just a rather basic quadratic equation that can be solved with the quadratic formula if need be

amistre64 · Answer

can you recall or look up the quadratic formula?

anonymous · Answer

Yeah. Nevermind, I got the answer. Thank you so much! :)

amistre64 · Answer

youre welcome, and good luck :)

anonymous · Answer

Thanks. :)