CALCULUS II - Average Values
f(x) = 6x/((1+x^2)^2), [0,2]

a) Find the average value f ave of f on the given interval.

b) Find c such that f ave = f(c).
There should be two answers.
Round your answers to three decimal places.

Question

CALCULUS II - Average Values
f(x) = 6x/((1+x^2)^2),  [0,2]

a) Find the average value f ave of f on the given interval.

b) Find c such that f ave = f(c).
There should be two answers.
Round your answers to three decimal places.

anonymous · Answer

I finished A.
A) 6/5

B) 6x/ ((1+x^2)^2) = 6/5

rational · Answer

A looks good

rational · Answer

you may use wolfram for part B http://www.wolframalpha.com/input/?i=solve+6%2F5+%3D++6x%2F%28%281%2Bx^2%29^2%29%2C+0%3Cx%3C2

anonymous · Answer

f(0)=6(0)/(1+(0)(0))^5=0
f(2)=6(2)/{1+2^2}^2=12/25
Av={0+(12/25)}/2=?

anonymous · Answer

Correction
f(0)=6*0/{ 1+0^2}^2=0