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Mathematics 21 Online
OpenStudy (anonymous):

Paula and Ricardo are serving cupcakes at a school party. If they arrange the cupcakes in groups of 2,3,4,5,or 6 they always have exactly one cupcake left over. What is the smallest number of cupcakes they could have?

OpenStudy (rational):

Suppose the number of cupcakes is \[\large 2*3*4*5*6 + 1\]

OpenStudy (anonymous):

so 721

OpenStudy (rational):

does it meet the given requirement that exactly one cupcake will be left if you arrange in groups of 2,3,4,5,6 ?

OpenStudy (anonymous):

well-----> 2+3+4+5+6=20 divided by 5=4

OpenStudy (anonymous):

so its 4

OpenStudy (anonymous):

no i dont think its 4

OpenStudy (anonymous):

i typed in that answer and it wrong

OpenStudy (anonymous):

why dont u think its 4?

OpenStudy (anonymous):

its*

OpenStudy (rational):

721 meets the given requirement but it is not the "smallest" number

OpenStudy (anonymous):

how do i find the smallest number?

OpenStudy (rational):

instead try this number \[\text{LCM}(2,3,4,5,6) + 1\]

OpenStudy (rational):

whats the LCM of 2,3,4,5,6 ?

OpenStudy (anonymous):

why dont u think its 4 @lizethv

OpenStudy (anonymous):

61?

OpenStudy (rational):

Yes! LCM of 2,3,4,5,6 is 60 adding 1 to that we get the required number : 60+1 = 61

OpenStudy (anonymous):

okay thank you!

OpenStudy (rational):

yw

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