Question

A line passes through (1, -4) and is parallel to the line 3x-8y+1=0. Find its equation

Answer 1

@pielover123

Answer 2

In what form?

Answer 3

Slope-intercept?

Answer 4

Standard?

Point-slope?

Answer 5

sorry i took so long

Answer 6

any line parallel will have the equation 3x +8y +c
you have to find c
put in (1,-4) and solve to get c

Answer 7

3x - 8y + 1 = 0

Convert to slope-intercept form:

Subtract 1 to both sides:

3x - 8y = -1

Subtract 3x to both sides:

-8y = -3x - 1

Divide -8 to both sides:

y = 3/8x + 1/8

Okay, what's the slope here? @~Gelmhar

Answer 8

3/8

Answer 9

sorry -8x typo

Answer 10

got it :D, can we proceed to another question :D

Answer 11

Correct, and parallel lines have the SAME slope..so the slope of our new line will have a slope of 3/8 also.

Now let's plug in (1, -4) and the slope of 3/8 into point-slope form.

\(y - y_1 = m(x - x_1)\)

Where \(y_1\) is the y-value of the point, \(x_1\) is the x-value of the point, and \(m\) is the slope.

Can you plug in the point and the slope?

Answer 12

Oh, what did you come up with?

Answer 13

im still solving it @iGreen

Answer 14

Okay, tell me what you come up with.

Answer 15

-3x +8y+35=0

Answer 16

or 3x-8y-35=0

Answer 17

@iGreen

Answer 18

That's incorrect..

Answer 19

Do you have options?

Answer 20

how did you know that is incorrect?

Answer 21

It isn't the same as the original line.

Answer 22

I get 3x-8y-35 also

Answer 23

Oh, wait, hold on.

Answer 24

That's correct, sorry..I just thought it had to be the same as that line..lol. My bad.

Answer 25

i substitute it correctly :D

Answer 26

Nice work! \(\Huge\color{lime} \checkmark\)

Answer 27

can you help me again igreen :D

Answer 28

Sure thing!