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Mathematics 16 Online
OpenStudy (anonymous):

Please Help. MEDAL AND FAN

OpenStudy (anonymous):

OpenStudy (anonymous):

@rational

OpenStudy (anonymous):

@tylermcmullen23

OpenStudy (anonymous):

the trick here is to use the Pythagorean theorem

OpenStudy (anonymous):

do you remember this equation?

OpenStudy (anonymous):

so 21 * 21

OpenStudy (anonymous):

8*8

OpenStudy (anonymous):

Is it like that

OpenStudy (anonymous):

it goes like this: a squared plus b squared equals c squared

OpenStudy (anonymous):

so your two sides that you know are a and b

OpenStudy (anonymous):

and you solve for c

OpenStudy (blake57roger):

this is easy

OpenStudy (anonymous):

the answer is 22.47220505424423 which when you round is 22.5

OpenStudy (blake57roger):

I thought it was C

OpenStudy (anonymous):

I could be wrong, can you show me how you got c?

OpenStudy (anonymous):

I haven't done this stuff in a long time

OpenStudy (blake57roger):

yea

OpenStudy (anonymous):

but when i squared my numbers I got 64 + 441 = csquared

OpenStudy (anonymous):

I added them to get 505 = csquared

OpenStudy (anonymous):

then I found the square root of them and got 22.5 = c

OpenStudy (rational):

\[\large a^2 + b^2 = c^2\] \[\large x^2 + 8^2 = 21^2\] solve \(x\)

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